Cryptarithmetic Problem - 2
H O W
x C U T
----------
D D C P
D W P W
D U O A
----------------
D C E P D P
| 1. | Value of T + O + P ? |
| (a) 3 | (b) 8 | (c) 6 | (d) 9 |
| 2. | Value of B ? |
| (a) 1 | (b) 2 | (c) 3 | (d) 4 |
| 3. | Value of 2C ? |
| (a) 13 | (b) 13 | (c) 17 | (d) 11 |
As, W x U= _ W [ D W P W ]
For W the probablities are-
Case-1 When W={2, 4, 8} and U={6}
For W the probablities are-
Case-2 When W={5} and U={3, 7, 9}
Taking the first scenerio
Take U=6 and problem looks like,
H O W
x C 6 T
----------
D D C P
D W P W
D 6 O A
----------------
D C E P D P
Getting more progress,
H O W
x C 6 T
----------
D D C P
D W P W
D 6 O A
----------------
D C E P D P
D + 6 + (carry) = C [Carry may be either 0, 1 or 2]
Hence, problem looks like of C= {7, 8, 9}
Start hit and trail C={7, 8, 9} and W={2, 4 ,8}
C=7 and W=2
when C=7 and W=2 then D=9 [ As, C + W = D] If we take take D=9 then,
H O W
x C 6 T
----------
D D C P
9 W P W
9 6 O A
----------------
0 C E P D P
D=0 and D=9 two values of D this C=7 and W=2(Not true)
Now, Check the with other possible values of W and C
Let's take C=7 and W=4
then D=1 as C + W = D [last digit]
Taking D=1, C=7 and W=4 now problems looks like
H O 4
x 7 6 T
----------
1 1 7 P
1 4 P 4
1 6 O A
----------------
1 7 E P 1 P
Now, you can easily predict the value of A=8 As, 7 x 4= _ A [last digit]
H O 4
x 7 6 T
----------
1 1 7 P
1 4 P 4
1 6 O 8
----------------
1 7 E P 1 P
Now,
H O 4
x 7
----------
1 6 O 8
You can easily predict the value of H=2
2 O 4
x 7 6 T
----------
1 1 7 P
1 4 P 4
1 6 O 8
----------------
1 7 E P 1 P
Now you can easily predict other values.
Value of T=5 O=3 and P=0
2 3 4
x 7 6 5
----------
1 1 7 0
1 4 0 4
1 6 3 8
----------------
1 7 9 0 1 0
H=2, O=3, W=4, C=7, U=6, T=5, D=1, S=0, E=9
2 3 4
x 7 6 5
------------
1 1 7 0
1 4 0 4
1 6 3 8
----------------
1 7 9 0 1 0
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